Palou to start second at Laguna Seca as McLaughlin takes pole
Translated from Spanish and summarized by DistantNews. Read the original for the full story.
At a glance
- Scott McLaughlin took pole position for the final IndyCar race of the season at Laguna Seca, with newly crowned champion Alex Palou qualifying second.
- McLaughlin posted 1:09.1363, narrowly ahead of Palouโs 1:09.1540.
- Palou leads the championship with 607 points, 100 more than Christian Lundgaard, and has won six races this season.
Scott McLaughlin will start the final IndyCar race of the season from pole at Laguna Seca, with Alex Palou alongside him on the front row.
The Team Penske driver completed the California circuit in 1:09.1363, slightly faster than Palouโs 1:09.1540. Palou, driving for Chip Ganassi, secured second place after winning the championship for a fifth time last week.
โWe went for it. We tried to get pole,โ Palou said after qualifying. โIโm very happy to start from the front row, and I think Scott had a very good lap.โ He said he had encountered problems during his lap but hoped to have a competitive car for the race and challenge for victory.
We went for it. We tried to get pole. Iโm very happy to start from the front row, and I think Scott had a very good lap.
Palou has already mathematically secured the title with 607 points, 100 ahead of his closest rival, Denmarkโs Christian Lundgaard of Arrow McLaren. The Catalan driver has won six races this season and has taken three victories at Laguna Seca, in 2022, 2024 and 2025.
โI love it. I love it. Every lap here,โ Palou said of the circuit. โThe atmosphere weโve had this weekend has been incredible. The weather, this circuit is the best.โ
I love it. I love it. Every lap here. The atmosphere weโve had this weekend has been incredible. The weather, this circuit is the best.
Originally published by ABC Color in Spanish. Translated, summarized, and contextualized automatically by DistantNews, with a note on how the source frames the story. Not individually reviewed before publishing. How this works.